what is the probability of getting a head when tossing 4 coins simultaneously

just one head? Means one head, three tails.

Pr= .5^4

I read that as a binomial distribution.

so
C(4,1) (1/2)^1 (1/2)^3
= 4(1/2)^4
= 1/4

or

there are 2^4 or 16 cases
your event could be
HTTT
THTT
TTHT
TTTH, or 4 possibilities
prob(exactly one head) = 4/16 = 1/4

I agree on 1/4, the answer I posted is of getting a HTTT, but there are four ways of getting a H (first, second, third, ..), or Pr=4/16 or 1/4

Thanks for checking Reiny.

To calculate the probability of getting a head when tossing multiple coins, we need to determine the total number of possible outcomes and the number of favorable outcomes.

When tossing a single coin, there are two possible outcomes: heads (H) or tails (T). Since we are tossing four coins simultaneously, the total number of possible outcomes increases exponentially. Each coin can independently land as either heads or tails, resulting in 2^4 = 16 total outcomes.

Now, we need to determine the number of favorable outcomes, which in this case is the number of outcomes where at least one coin lands on heads. To count these outcomes, we can consider the complement. That is, we count the number of outcomes where all four coins land on tails, and subtract this from the total outcomes.

Since each coin has two possible outcomes (heads or tails), the number of outcomes where all four coins land on tails is 2^4 = 16. Thus, there is only one favorable outcome (all coins landing on heads) out of the total of 16 outcomes.

Therefore, the probability of getting a head when tossing four coins simultaneously is 1/16, or approximately 0.0625.