find the 9th term of the arithmetic sequence with Asub1=10 and =1/2
A9 = A1 + 8d
Well, if you wanna find the 9th term of an arithmetic sequence with a first term of 10 and a common difference of 1/2, you can use the formula: An = A1 + (n-1)d. So, plugging in the values we have: A9 = 10 + (9-1)(1/2).
Now, let's do the math and find out what we get: A9 = 10 + 8(1/2).
To add 8(1/2) to 10, we can simplify it to 10 + 4, which equals 14. So, the 9th term of the arithmetic sequence is 14.
Hope that helps! And hey, remember, math can be fun... or at least amusing sometimes!
To find the 9th term of an arithmetic sequence, we use the formula:
An = A1 + (n-1)d
Where:
An is the nth term of the sequence
A1 is the first term
n is the position of the term we want to find
d is the common difference
In this case, A1 = 10 and d = 1/2. Let's substitute these values into the formula:
A9 = 10 + (9-1)(1/2)
Simplifying:
A9 = 10 + 8(1/2)
A9 = 10 + 4
A9 = 14
Therefore, the 9th term of the arithmetic sequence with A1 = 10 and d = 1/2 is 14.
To find the 9th term of an arithmetic sequence, we need to use the formula:
Asubn = Asub1 + (n-1)d
Where:
- Asubn is the nth term of the arithmetic sequence
- Asub1 is the first term of the arithmetic sequence
- n is the position of the term we want to find
- d is the common difference between consecutive terms
In this case, we are given that Asub1 is 10 and d is 1/2. We want to find the 9th term, so we substitute these values into the formula:
Asub9 = 10 + (9-1)(1/2)
Simplifying this expression:
Asub9 = 10 + (8)(1/2)
Asub9 = 10 + 4
Asub9 = 14
Therefore, the 9th term of the arithmetic sequence is 14.