A molecule has 8percent sulphur.this Will have minimum molecular mass

To determine the minimum molecular mass of a molecule with 8% sulphur, we need to consider the atomic masses of sulfur and other elements present in the molecule.

First, let's assume the molecule is composed of only sulfur (S) atoms. The atomic mass of sulfur is 32.06 g/mol (rounded to two decimal places).

To calculate the minimum molecular mass, we need to know the number of sulfur atoms in one mole of the molecule. Since the percentage of sulfur in the molecule is 8%, it means that 8 grams of the molecule contain 1 gram of sulfur.

Using the atomic mass of sulfur, we can calculate the number of sulfur atoms in 8 grams:

Number of moles of sulfur = Mass of sulfur / Atomic mass of sulfur
Number of moles of sulfur = 8 g / 32.06 g/mol = 0.249 moles

To find the number of sulfur atoms, we multiply the number of moles of sulfur by Avogadro's number (6.022 x 10^23 atoms/mol):

Number of sulfur atoms = Number of moles of sulfur x Avogadro's number
Number of sulfur atoms = 0.249 moles x 6.022 x 10^23 atoms/mol = 1.498 x 10^23 atoms

Now, we know that the molecular mass is the mass of one molecule, which is equal to the mass of one sulfur atom.

Minimum molecular mass = Mass of one sulfur atom = Atomic mass of sulfur
Minimum molecular mass = 32.06 g/mol

Therefore, the minimum molecular mass of a molecule with 8% sulfur is 32.06 g/mol.