If potassium chlorate is 80 percent pure ,then 48gram of oxygen would produced from how many gram of potassiumchlorate

2KClO3 ==> 2KCl + 3O2

mols O2 needed = grams/molar mass = 48/32 = about 1.5?
Using the coefficients in the balanced equation, convert mols O2 to mols KClO3. That's 1.5 mols O2 x (2 mols KClO3/3 mols O2) = 1.5 x 2/3 = about 1
So you need 1 mol KClO3 which is grams = mols x molar mass = 1 mol x 122.5 = 122.6 grams IF it were pure. It isn't.
122.6/0.8 = ? if it is 80% pure.

2KClO3=2KCl+3O2.So 245g of KClO3 produces 96g of oxygen.So 122.5g of KClO3 produces 48g of oxygen.This is when it’s 100% pure.But it’s 80% pure.So therefore 152.12 g of KClO3 is required

Thank U do more solutions

To find out how many grams of potassium chlorate would produce 48 grams of oxygen, we first need to determine the molar mass of potassium chlorate.

The molecular formula of potassium chlorate (KClO3) consists of one potassium atom (K), one chlorine atom (Cl), and three oxygen atoms (O).

The atomic mass of potassium (K) is approximately 39.1 grams per mole, the atomic mass of chlorine (Cl) is approximately 35.5 grams per mole, and the atomic mass of oxygen (O) is approximately 16 grams per mole.

Therefore, the molar mass of one molecule of potassium chlorate (KClO3) can be calculated as follows:

(1 * 39.1) + (1 * 35.5) + (3 * 16) = 122.5 grams per mole

Now, we can determine the number of moles of potassium chlorate required to produce 48 grams of oxygen.

To do this, we can use the ratio of the molar mass of potassium chlorate to the molar mass of oxygen:

(48 grams * 1 mole of KClO3) / (16 grams * 3 moles of O)

Calculating further:

48 grams * 1 mole of KClO3 = (48 / 122.5) moles of KClO3
16 grams * 3 moles of O = 48 grams of O

So, to produce 48 grams of oxygen, approximately 0.392 moles of potassium chlorate are required.

Finally, to find out the mass of potassium chlorate required, we multiply the number of moles by the molar mass:

0.392 moles * 122.5 grams per mole = approximately 48 grams of potassium chlorate

Simple 100./.means 122.5g

80./. Means 122.5*8o./.

122.5×0.8