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Find the equation of a line pass through (-2, 5) and ( 3,4 )
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find the slope, then use the steps I showed you in your first post
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Matriliny refers to societies in which property and status __________.
a. pass through the male line b. return to the state c.
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d. pass through the female line
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find the equation of a line whose slope is 8 and pass through the point (-2,1)
a). y=8x-2 b). y=8x 17 c). y=9-2x d). y=x 6?
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(-2, 1), m = 8. Y = mx + b. 1 = 8*(-2) + b, b = 17. Y = 8x + 17.
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No solution seen
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(y-0)/(x-3) = (1-0)/(2-3) y = (x-3) ( 1/-1) = -x + 3 y = -x + 3 =========== check ======== (3,0)? y
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Find the equation of the line that pass through the given point and is perpendicular to the given line. Write in slope intercept
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Rewrite it as y = -(1/3)x -12 That tells you that the slope of the original line is -1/3. The slope
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Find the equations of the lines that pass through the point (5, 5) and are parallel to and perpendicular to the line with the
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as before, you want lines with slopes -2 and 1/2 so use the point-slope form
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find an equation for the line with the given properties. express the equation in slope-intercept form.
containing the
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To find the equation of a line in slope-intercept form (y = mx + b), we need to find the slope (m)
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Write an equation of the line that pass through point P and is parallel to the line with the given equation.
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Top answer:
since y=4 is a horizontal line, you want a horizontal line that passes through P, where y=5. Oops
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Write an equation of the line that pass through point P and is perpendicular to the line with the given equation.
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This is a horizontal line, so a perpendicular line gives you a constant x value, providing the
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will pass two
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