Rain drops fall on a tile surface at a density
of 4585 drops/ft2
. There are 15 tiles/ft2
.
How many drops fall on each tile?
Answer in units of drops/tile.
4585/15
or to do it the physics way:
(4585 drops/ft^2)*(1 ft^2/15 tiles)
= (4585 drops/ 15 tiles)
Rain drops fall on a tile surface at a density
of 4783 drops/ft2
. There are 12 tiles/ft2
To find out how many drops fall on each tile, we need to divide the total number of drops by the total number of tiles.
First, let's calculate the total number of drops. We are given that the rain drops fall at a density of 4585 drops/ft^2. Since there are 15 tiles/ft^2, we can calculate the total number of drops per ft^2 by multiplying the density of drops/ft^2 by the number of tiles/ft^2:
Total drops/ft^2 = Density of drops/ft^2 * Number of tiles/ft^2
Total drops/ft^2 = 4585 drops/ft^2 * 15 tiles/ft^2
Next, let's cancel out the units and perform the multiplication:
Total drops/ft^2 = (4585 * 15) drops/tile
Total drops/ft^2 = 68775 drops/tile
Therefore, there are 68775 drops that fall on each tile.