What mass of water is produced from 10g of sulfuric acid ?

How many moles of H2SO4 in 10g

How many moles of H2O for each mole of H2SO4?
How many grams per mole of H2O?

To determine the mass of water produced from 10g of sulfuric acid, we need to use the balanced chemical equation for the reaction in which sulfuric acid forms water. The chemical equation is:

H2SO4 + H2O -> H2SO4

From the equation, we can see that 1 mole of sulfuric acid (H2SO4) will produce 1 mole of water (H2O).

First, we need to convert the given mass of sulfuric acid (10g) into moles. To do this, we divide the given mass by the molar mass of sulfuric acid. The molar mass of H2SO4 is approximately 98g/mol (2g (2 * 1) + 32g (1 * 32) + 16g (4 * 16)).

10g / 98g/mol = 0.102 mol

Since the molar ratio between sulfuric acid and water is 1:1, we can conclude that 0.102 moles of sulfuric acid will produce 0.102 moles of water.

To calculate the mass of water, we multiply the number of moles by its molar mass. The molar mass of water (H2O) is approximately 18g/mol (2g (2 * 1) + 16g (1 * 16)).

0.102 mol * 18g/mol = 1.836g

Therefore, approximately 1.836g of water is produced from 10g of sulfuric acid.