A bullet is moving with speed of 500m/s. Hit the target and penetrate 100mm into the target. Find the retardation of the bullet.
V^2 = Vo^2 + 2a*d.
V = 0, Vo = 500 m/s, d = 0.10 m, a = ?.
"a" will be negative.
To find the retardation of the bullet, we can use the equation of motion relating the initial velocity, final velocity, acceleration, and displacement. Since the bullet hits the target and penetrates into it, we assume that the retardation is constant.
The equation we will use is:
v^2 = u^2 + 2as
where:
v = final velocity (which is 0 since the bullet comes to rest)
u = initial velocity (500 m/s)
a = acceleration (retardation in this case)
s = displacement (100 mm = 0.1 m)
Rearranging the equation, we get:
a = (v^2 - u^2) / (2s)
Substituting the given values:
a = (0 - (500^2)) / (2 * 0.1)
Calculating further:
a = (-250000) / 0.2
a = -1250000 m/s^2
Therefore, the retardation of the bullet is -1250000 m/s^2, where the negative sign indicates that the bullet is decelerating.