A car traveling at 18 m/s accelerates at 3.31 m/s2 for 9 seconds. To the nearest meter how far does it travel?
just plug in your basic equation of motion:
s = vt + 1/2 at^2
Now just use your numbers for v and a and t.
To find the distance the car traveled, we can use the formula:
distance = initial velocity * time + (1/2) * acceleration * time^2.
First, let's identify the given values:
Initial velocity (u) = 18 m/s
Acceleration (a) = 3.31 m/s²
Time (t) = 9 seconds
Plugging the values into the formula:
distance = (18 m/s * 9 s) + (1/2) * (3.31 m/s²) * (9 s)^2
To calculate the answer, we need to solve this equation step by step:
1. Calculate the velocity after 9 seconds using the formula:
final velocity (v) = initial velocity (u) + acceleration (a) * time (t).
v = 18 m/s + 3.31 m/s² * 9 s
v ≈ 18 m/s + 29.79 m/s
v ≈ 47.79 m/s
2. Substitute the calculated final velocity into the distance formula:
distance = (18 m/s * 9 s) + (1/2) * (3.31 m/s²) * (9 s)^2
distance ≈ 162 m + (1/2) * 3.31 m/s² * 81 s²
distance ≈ 162 m + 1.655 m/s² * 81 s²
distance ≈ 162 m + 133.755 m
distance ≈ 295.755 m
Therefore, the car travels approximately 295.755 meters.