a car travelling at 60km/h uniformly retards for 10s and reaches a velocity of 45km/h. find the retardation.
60,000 /3600 = 16.7 m/s
45,000 /3600 = 12.5 m/s
v =Vi + a t
12.5 = 16.7 + 10 a
a = -0.42 meters/second^2
NICKEL PAHLI FURSAT ME
Velosity me
To find the retardation (deceleration) of the car, we can use the formula:
Retardation (a) = Change in velocity (Δv) / Time (t)
Given:
Initial velocity (u) = 60 km/h
Final velocity (v) = 45 km/h
Time taken (t) = 10 s
First, let's convert the velocities from km/h to m/s since the formula requires velocity in meters per second (m/s).
1 km/h = 1000 m/3600 s = 5/18 m/s
Initial velocity (u) = 60 km/h × 5/18 m/s = 50/3 m/s
Final velocity (v) = 45 km/h × 5/18 m/s = 25/2 m/s
Now we can substitute the values into the formula:
Retardation (a) = (v - u) / t
= (25/2 - 50/3) / 10
= (75 - 100) / (6 × 10)
= -25 / 60
= -5/12 m/s²
Therefore, the retardation of the car is -5/12 m/s². Note that the negative sign indicates it is decelerating or slowing down.
A car travelling by you
or,
-1.5 km/hr/s