Find the hang time for a golf ball hit 150 feet into the air. The time T in seconds is given by the function
T(x)= square root of x over 2
I assume x is the height in feet ?
is it T(x) = √x/2 or √(x/2) ??
if will assume the first,
t(150) = √150/2 = appr 6.12 seconds
If I assumed incorrectly, repeat my steps using the second equation.
To find the hang time of a golf ball, we need to determine the time it takes for the ball to reach its maximum height and then return to the ground.
The given function, T(x) = √x/2, represents the time T in seconds as a function of the height x in feet.
Since the ball is hit 150 feet into the air, we can substitute x = 150 into the function to find the hang time.
T(150) = √150/2
To simplify the expression, we can find the square root of 150:
T(150) = √150/2 = 12.25/2 = 6.125 seconds
Therefore, the hang time for the golf ball is approximately 6.125 seconds.
To find the hang time for a golf ball hit 150 feet into the air, we can use the given function T(x) = √x/2, where x represents the height of the ball in feet and T(x) represents the hang time in seconds.
In this case, x = 150 feet. So, we need to find T(150).
Substituting the value of x into the function, we get:
T(150) = √150/2
To simplify this expression, calculate the square root of 150:
√150 ≈ 12.247
Now divide it by 2:
12.247/2 ≈ 6.1235
Therefore, T(150) ≈ 6.1235 seconds.
The hang time for a golf ball hit 150 feet into the air is approximately 6.1235 seconds.