According to the Lewis Acid/Base theory, what is the neutralization equation of Acid Nacl and Base AlCl3? NaCl+AlCl3---->
(NaCl+AlCl3-----> Na+AlCl4 is incorrect)
Based on the Lewis Acid/Base theory, a Lewis acid is a species that can accept an electron pair, and a Lewis base is a species that can donate an electron pair. In the neutralization reaction between an acid and a base, the Lewis acid will accept an electron pair from the Lewis base, forming a coordinate covalent bond.
In the case of your question, the acid is NaCl (which contains the Cl- ion) and the base is AlCl3 (which contains the AlCl4- ion). To determine the Lewis neutralization equation, we need to identify the species that can donate an electron pair (Lewis base) and the species that can accept an electron pair (Lewis acid).
In this case, the Cl- ion in NaCl can act as the Lewis base, as it can donate its lone pair of electrons. The AlCl3 molecule, as a whole, can act as the Lewis acid since it can accept a pair of electrons.
Therefore, the Lewis neutralization equation can be written as follows:
Cl- (from NaCl) + AlCl3 → [ClAlCl3]-
The Lewis base (Cl-) donates its lone pair of electrons to the Lewis acid (AlCl3) to form a coordinate covalent bond. As a result, AlCl3 gains an extra electron and forms an anion [ClAlCl3]-.
It's important to note that Lewis acids and bases are not restricted to proton transfer reactions (as in the Brønsted-Lowry theory), but can involve the sharing of electron pairs as well.