An 85.0 kg man playing hockey catches a puck moving at 25.0 m/s. The man is initially at rest. The man and the puck move together after the collision. The puck's mass is 0.16 kg. What is the final velocity?
0.05
momentum is conserved
.16 * 25 = (85 + .16) * v
To determine the final velocity of the man and the puck after the collision, we can use the law of conservation of momentum.
According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Mathematically, this can be expressed as:
Momentum before collision = Momentum after collision
The momentum of an object is calculated by multiplying its mass by its velocity. Therefore, we can write the equation as:
(mass of the man * initial velocity of the man) + (mass of the puck * initial velocity of the puck) = (mass of the man + mass of the puck) * final velocity
Now, let's plug in the given values into the equation:
(85.0 kg * 0 m/s) + (0.16 kg * 25.0 m/s) = (85.0 kg + 0.16 kg) * final velocity
0 + 4.0 kg·m/s = 85.16 kg * final velocity
Dividing both sides of the equation by 85.16 kg gives us:
0.047 kg·m/s = final velocity
Therefore, the final velocity of the man and the puck after the collision is approximately 0.047 m/s.