∫4x^−1*sin(ln(6x))dx
I got 4*[-cos(ln(6x))]+C
but its wrong and im not sure why...
Please Help!!
Thanks
well, try this backwards assuming you answered correctly
y = -4 cos [ ln(6x) ]
dy/dx = -4 (-sin [ln(6x)]*6/6x
= 4 sin [ln(6x)] / x
I see nothing wrong with your answer.