I am 4 digit number my hundreds digit is 5 less than my ones digit and my thousands digit is one half of my tens digit. What number am i?
Could be any one of several, starting with 4489, 3368, 2247....
Do you have more data?
Let's break down the information given step-by-step:
Step 1: The hundreds digit is 5 less than the ones digit.
Let's denote the hundreds digit as 'A' and the ones digit as 'B'. According to the information given, we can write the equation:
A = B - 5
Step 2: The thousands digit is one half of the tens digit.
Let's denote the thousands digit as 'C' and the tens digit as 'D'. According to the information given, we can write the equation:
C = D/2
Now, we need to find the specific 4-digit number that satisfies these conditions:
Step 3: Since we have a 4-digit number, we know that:
A, B, C, and D are integers between 0 and 9.
Step 4: To find the number, we can start testing different values for D and solve for the other variables.
Let's start with D = 2:
Using the equation C = D/2, we find C = 1.
Using the equation A = B - 5, we find A = -3, which is not a valid digit since it is less than 0.
Therefore, D = 2 does not satisfy the conditions.
Let's continue testing different values for D:
D = 3:
Using the equation C = D/2, we find C = 1.5, which is not an integer between 0 and 9.
Therefore, D = 3 does not satisfy the conditions.
D = 4:
Using the equation C = D/2, we find C = 2.
Using the equation A = B - 5, we find A = -1, which is not a valid digit since it is less than 0.
Therefore, D = 4 does not satisfy the conditions.
D = 5:
Using the equation C = D/2, we find C = 2.5, which is not an integer between 0 and 9.
Therefore, D = 5 does not satisfy the conditions.
D = 6:
Using the equation C = D/2, we find C = 3.
Using the equation A = B - 5, we find A = 1, which is a valid digit.
Therefore, the number is 1362.
In conclusion, the number satisfying the given conditions is 1362.
To solve this problem, we can use the given information to help determine the unknowns. Let's break down the information:
1. "My hundreds digit is 5 less than my ones digit": Let's denote the hundreds digit as H and the ones digit as O. This can be written as H = O - 5.
2. "My thousands digit is one half of my tens digit": Let's denote the thousands digit as T. This can be written as T = (1/2) * T.
Based on the second piece of information, it seems there is a typo. It should be "My thousands digit is one half of my tens digit." The equation should be T = (1/2) * D, where D denotes the tens digit.
Since it is a four-digit number, we can assign X as the number itself. Therefore, the number can be written as:
X = 1000 * T + 100 * H + 10 * D + O
By substituting the values we found in steps 1 and 2, we get:
X = 1000 * ((1/2) * D) + 100 * (O - 5) + 10 * D + O
Now, we can simplify the equation to find the value of X:
X = 500D + 100O - 500 + 10D + O
Combining like terms, we get:
X = 510D + 101O - 500
Since X is a four-digit number, it means that X is between 1000 and 9999. Let's check for all possible values of D and O within their respective ranges to find the value that satisfies the equation.
Using this process, we find that when D = 7 and O = 2, X = 7312.
Therefore, the number you are is 7312.