C3H8 + 5O2 --> 3CO2 + 4H2O

22 moles of propane (C3H8) react with 200 moles of oxygen gas. how many moles of the non limiting reactant remain?

i got the liming reactant is C3H8 and the moles of CO2 produced is 66.

To find out how many moles of the non-limiting reactant remain, we first need to identify the limiting reactant. The limiting reactant is the reactant that runs out first and determines the amount of product that can be formed.

To find the limiting reactant, we need to compare the molar ratios between the reactants and the products based on the balanced chemical equation.

According to the balanced equation:
1 mole of C3H8 reacts with 5 moles of O2.

To determine how many moles of O2 are required for 22 moles of C3H8 to react, we can set up a proportion:

(22 moles C3H8) / (1 mole C3H8) = (x moles O2) / (5 moles O2)

Cross-multiplying, we get:
22 moles C3H8 = x moles O2 / 5

Simplifying, we find:
x moles O2 = 22 moles C3H8 * (5 moles O2 / 1 mole C3H8)
x moles O2 = 110 moles O2

Now, we compare the calculated amount of O2 required (110 moles) with the amount provided (200 moles). Since 200 moles of O2 is more than what is required (110 moles), O2 is in excess, and C3H8 is the limiting reactant.

Therefore, all the 200 moles of O2 will be completely consumed, and there will be no O2 remaining.

To find out how many moles of the non-limiting reactant (C3H8) remain, we can use a similar approach.

Since we know that 22 moles of C3H8 reacted, we can subtract this amount from the initial amount provided (22 moles):

Remaining moles of C3H8 = Initial moles of C3H8 - Moles of C3H8 that reacted
Remaining moles of C3H8 = 22 moles - 22 moles
Remaining moles of C3H8 = 0 moles

Therefore, there are 0 moles of C3H8 remaining.