A BRICK WITH MASS OF 6 KG IS DROPPED VERTICALLY FROM A CERTAIN HEIGHT. IT TAKES 4.5 SECONDED FOR THE BRICK TO REACH THE GROUND DETERMINE THE FF. THE HEIGHT FROM WHICH THE BRICK IS DROPPED
THE SPEED OF WHICH THE BRICK THE GROUND IT AND THE MOMENTUM OF THE BRICK THE MOMENT JUST BEFORE THE GROUND IT
h=1/2 g t^2 solve for height
vf=g*t solve for ending velocity
momemtum=mass*velocity
Please stop using capital letters, it is difficult to read.
To determine the height from which the brick is dropped, we can use the equation for free fall motion:
h = (1/2) * g * t^2
Where:
h = height
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time taken (4.5 seconds in this case)
Plugging in the values, we get:
h = (1/2) * 9.8 * (4.5)^2
h = 99.225 meters
Therefore, the height from which the brick is dropped is approximately 99.225 meters.
To calculate the speed of the brick just before it hits the ground, we can use the equation for final velocity:
v = g * t
Plugging in the values, we get:
v = 9.8 * 4.5
v = 44.1 m/s
Therefore, the speed of the brick just before it hits the ground is approximately 44.1 m/s.
The momentum of the brick just before it hits the ground can be calculated using the formula:
p = m * v
Where:
p = momentum
m = mass of the brick (6 kg)
v = velocity of the brick just before hitting the ground (44.1 m/s)
Plugging in the values:
p = 6 * 44.1
p = 264.6 kg·m/s
Therefore, the momentum of the brick just before it hits the ground is approximately 264.6 kg·m/s.