A sample of beer is 4.6% by Mass C2H5OH. The density of beer is 0.93 g/mL. What is the molar concentration of C2H5OH in this sample of beer?
assume a liter of beer...
Molarity=molesalcho/1
but mass alcohol=.046*.93*1000= you do it.
Molarity=massalcohol/MolmassC2H5OH
and there you have it.
So the answer is:
43.78 / 46.068 = 0.929 M?
recheck your mass alcohol...
.046*.93*1000= in your google search window
To find the molar concentration of C2H5OH in the beer sample, we need to determine the amount of C2H5OH in moles and then divide by the volume of the beer sample.
First, we need to calculate the mass of C2H5OH in the beer sample. Since the beer is 4.6% by Mass C2H5OH, we can calculate it as follows:
Mass of C2H5OH = (4.6/100) * Mass of beer
Next, we need to calculate the moles of C2H5OH. To do this, we will use the molar mass of C2H5OH, which is the sum of the atomic masses of its constituent elements. The molar mass of C2H5OH is:
Molar mass of C2H5OH = (2 * atomic mass of C) + (6 * atomic mass of H) + atomic mass of O
Finally, we can calculate the molar concentration of C2H5OH using the formula:
Molar concentration = (moles of C2H5OH) / (volume of beer in liters)
We will also convert the density of beer from g/mL to g/L, as the volume should be in liters for calculations. Therefore, the final formula to calculate the molar concentration is:
Molar concentration = [(4.6/100) * Mass of beer] / [((2 * atomic mass of C) + (6 * atomic mass of H) + atomic mass of O) * (density of beer in g/L)]
Plug in the respective values of the mass of beer and density of beer to calculate the molar concentration of C2H5OH in the beer sample.