the displacement of a particle moving in straight line is given by x= 16t-2t^2 find out displacement travelled after 2 and 6 second
Can you find distance at t=6 for the same
To find the displacement traveled after 2 and 6 seconds, substitute the given time values into the equation x = 16t - 2t^2 and calculate the values.
1. Displacement after 2 seconds:
Substitute t = 2 into the equation x = 16t - 2t^2:
x = 16(2) - 2(2)^2
x = 32 - 2(4)
x = 32 - 8
x = 24
Therefore, the displacement after 2 seconds is 24 units.
2. Displacement after 6 seconds:
Substitute t = 6 into the equation x = 16t - 2t^2:
x = 16(6) - 2(6)^2
x = 96 - 2(36)
x = 96 - 72
x = 24
Therefore, the displacement after 6 seconds is also 24 units.
To find the displacement traveled after 2 and 6 seconds, we need to substitute the given values into the equation x = 16t - 2t^2 and calculate the respective displacements.
1. Displacement after 2 seconds:
Substituting t = 2 into x = 16t - 2t^2,
x = 16(2) - 2(2)^2
= 32 - 2(4)
= 32 - 8
= 24
Therefore, the displacement traveled after 2 seconds is 24 units.
2. Displacement after 6 seconds:
Substituting t = 6 into x = 16t - 2t^2,
x = 16(6) - 2(6)^2
= 96 - 2(36)
= 96 - 72
= 24
Therefore, the displacement traveled after 6 seconds is also 24 units.
Thus, the particle travels a displacement of 24 units after 2 and 6 seconds.
just plug in values for t:
x(2) = 16*2 - 2*2^2 = 32-8 = 24
likewise for t=6