d/f coes each consisting of 5 characters are to be generated. In each code the first two characters are A or B and the remaining three characters are any of the digits 0,1,2,...9 How many distinict codes be generated so? please tell me the answer
Whatever "d/f coes" are, the must look like
ABxxx, where x is one of the given digits.
I will assume that repetition is allowed.
no. of ways = (1)(10)(10)(10) = 1000
4000
To find the number of distinct codes that can be generated, we need to consider the different possibilities for each character in the code.
For the first character, it can be either A or B, so there are 2 possibilities.
For the second character, it can also be either A or B, so again there are 2 possibilities.
For the remaining three characters, they can be any of the digits from 0 to 9, so there are 10 possibilities for each character.
To find the total number of distinct codes, we simply multiply the number of possibilities for each character:
2 (possibilities for the first character) * 2 (possibilities for the second character) * 10 (possibilities for each of the remaining three characters) = 2 * 2 * 10 * 10 * 10 = 4,000.
Therefore, there are 4,000 distinct codes that can be generated.