A triangle has a perimeter of 39 inches. If two sides are of equal length and the third side is 3 inches longer than either of the other two, how long is the longest side?
12+12=24
24+6=30
30+9=39
6+9=15
15-12=3
Therefore the two shorter sides are 12cm and the longest side is 15cm.
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Jaakkak
To solve this problem, let's assign variables to the lengths of the sides of the triangle.
Let's say the length of the two equal sides is 'x', and the length of the third side (longest side) is 'x + 3'.
The perimeter of a triangle is the sum of the lengths of its sides. In this case, the perimeter is given as 39 inches. Therefore, we can write the equation:
x + x + (x + 3) = 39
Simplifying the equation, we have:
3x + 3 = 39
Subtracting 3 from both sides:
3x = 36
Dividing both sides by 3:
x = 12
Therefore, the lengths of the two equal sides are 12 inches each, and the length of the longest side is:
x + 3 = 12 + 3 = 15 inches
So, the longest side of the triangle is 15 inches.
Let x = one of the shorter sides.
2x + x + 3 = 39
3x = 36
x = ?