98.4 * (1/2)^(19/3.8) = 3.075 g

CH3COOH***
H2PO4^–
LiOH
NH3

Ignore the numbers haha. the question is "Which of the following is an Arrhenius base" My computer glitched and mixed up the question

I believe the original definition for an Arrhenius base was that a base material contained the OH ion. LiOH would be the answer for this question. I believe the definition was expanded somewhat, later, to include anything that produced an OH ion in aqueous solution. As such, NH3 would qualify because

NH3 + HOH ==> NH4^+ + OH^-

To calculate the value of the expression 98.4 * (1/2)^(19/3.8), you can follow these steps:

1. Evaluate the exponent (19/3.8): Divide 19 by 3.8 to get the value 5.
(19 / 3.8) = 5

2. Rewrite the expression with the calculated exponent:
98.4 * (1/2)^5

3. Calculate the value of (1/2)^5:
(1/2)^5 = (1/32)

4. Substitute the value back into the expression:
98.4 * (1/32)

5. Multiply the two numbers:
98.4 * (1/32) = 3.075

Therefore, the result of the expression 98.4 * (1/2)^(19/3.8) is 3.075 g.

As for the list of compounds you provided:

CH3COOH represents acetic acid.
H2PO4^– represents the dihydrogen phosphate ion.
LiOH represents lithium hydroxide.
NH3 represents ammonia.