Two boat A and B left a port at the same time on different route. B traveled on the bearing of 150 degree and A traveled on the north side of B when had traveled 8 kilometer and B had traveled 10 kilometer. The distance between the two boat was found to be 12 kilometer. Calculate the bearing of the A's route from C.

Question

Two boat A and B left a port at the same time on different route. B traveled on the bearing of 150 degree and A traveled on the north side of B when had traveled 8 kilometer and B had traveled 10 kilometer. The distance between the two boat was found to be 12 kilometer. Calculate the bearing of the A's route from C.

Answer 1

I don't understand your question.

Please proofread and repost.
Where does C suddenly come from ?

Answer 2

Now i solved this problem and it happened to be very faulty because the answer i got does not correspond to the drawing given.....therefore the Questions parameters are incorrect further making the solution inconclusive.

Answer 3

show the steps and working

Answer 4

falade pls show steps

Answer 5

Pls that is how my master gave it to me.on attempt i got tita =41.

Answer 6

To calculate the bearing of A's route from C, we need to determine the angle between the north direction and A's route. Let's break down the problem and solve it step by step.

First, let's label the given information:

- Boat A traveled 8 kilometers.
- Boat B traveled 10 kilometers.
- The distance between the two boats (C) is 12 kilometers.

Next, let's draw a diagram to visualize the situation:

B (10 km)
/
/
/
A (8 km) /
/ 12 km
/
C

To find the bearing of A's route from C, we need to determine the angle between the north direction and A's route. We can do this by using trigonometry.

Using the Law of Cosines, we can find the angle between Boat A's route and the north direction:

cos(Angle) = (c^2 + a^2 - b^2) / (2 * c * a)

In our case:
- c = distance of 12 km (the distance between the two boats)
- a = distance of 8 km (Boat A's travel distance)
- b = distance of 10 km (Boat B's travel distance)

Plugging in the values, we have:

cos(Angle) = (12^2 + 8^2 - 10^2) / (2 * 12 * 8)
cos(Angle) = (144 + 64 - 100) / 192
cos(Angle) = 108 / 192
cos(Angle) ≈ 0.5625

Next, we need to find the Angle itself. We can use the inverse cosine function (arccos) to solve for the Angle:

Angle ≈ arccos(0.5625)
Angle ≈ 56.74 degrees

Therefore, the bearing of A's route from C is approximately 56.74 degrees.