A police cruiser is travelling at 24 m/s and slows down at a rate of 0.65 m/s2 until it stops. The distance traveled by the cop while slowing down is closest to

To determine the distance traveled by the police cruiser while slowing down, we need to calculate the stopping distance. The stopping distance can be determined using the equation:

Stopping Distance = (Initial Velocity^2) / (2 * Deceleration)

Given:
Initial velocity (u) = 24 m/s
Deceleration (a) = -0.65 m/s^2 (negative because it is slowing down)

Plugging in the values into the equation, we get:

Stopping Distance = (24^2) / (2 * (-0.65))

Calculating this, we get:

Stopping Distance = 576 / -1.3

Stopping Distance = -444.62 meters

Note: The negative sign indicates that the direction of motion is opposite to the initial motion.

However, distance is a scalar quantity and cannot be negative in this context. Therefore, the magnitude of the stopping distance is 444.62 meters.

Thus, the distance traveled by the police cruiser while slowing down is closest to 444.62 meters.

To calculate the distance traveled by the police cruiser while slowing down, we need to use the formula of motion:

d = (v^2 - u^2) / (2a)

Where:
d = distance
v = final velocity
u = initial velocity
a = acceleration

In this case, the initial velocity (u) of the police cruiser is 24 m/s, and it slows down at a rate of 0.65 m/s^2 until it stops, which means the final velocity (v) will be 0 m/s.

Plugging these values into the formula, we have:

d = (0^2 - 24^2) / (2 * -0.65)

Simplifying further, we get:

d = (0 - 576) / (-1.3)
d = -576 / (-1.3)
d ≈ 443.08 meters

Therefore, the distance traveled by the police cruiser while slowing down is closest to 443.08 meters.