How many grams of zinc chloride are required to react with 15 grams of aluminum metal to create aluminum chloride and zinc metal?
To find out how many grams of zinc chloride are required to react with 15 grams of aluminum metal, we first need to determine the balanced chemical equation for the reaction between zinc chloride and aluminum.
The balanced equation is as follows:
2 Al + 3 ZnCl2 → 2 AlCl3 + 3 Zn
From the balanced equation, we can see that the molar ratio between aluminum and zinc chloride is 2:3. This means that for every 2 moles of aluminum, we need 3 moles of zinc chloride.
Now, let's calculate the number of moles of aluminum:
Molar mass of aluminum (Al) = 26.98 g/mol
Number of moles = Mass / Molar mass
Number of moles of aluminum = 15 g / 26.98 g/mol = 0.556 mol (rounded to three decimal places)
According to the molar ratio, we need 3 moles of zinc chloride for every 2 moles of aluminum. Therefore, for 0.556 mol of aluminum, we will need:
Number of moles of zinc chloride = (3/2) * 0.556 mol = 0.834 mol
Lastly, let's calculate the mass of zinc chloride:
Molar mass of zinc chloride (ZnCl2) = 65.38 g/mol
Mass of zinc chloride = Number of moles * Molar mass
Mass of zinc chloride = 0.834 mol * 65.38 g/mol = 54.47 g (rounded to two decimal places)
Therefore, approximately 54.47 grams of zinc chloride are required to react with 15 grams of aluminum metal to create aluminum chloride and zinc metal.
To determine the number of grams of zinc chloride required to react with 15 grams of aluminum metal, we need to balance the chemical equation for the reaction between aluminum and zinc chloride.
The balanced chemical equation for the reaction is:
2 Al + 3 ZnCl2 -> 2 AlCl3 + 3 Zn
From the balanced equation, we can see that 2 moles of aluminum react with 3 moles of zinc chloride to produce 2 moles of aluminum chloride and 3 moles of zinc.
To solve the problem, we'll follow these steps:
Step 1: Calculate the number of moles of aluminum using its molar mass.
The molar mass of aluminum (Al) is 26.98 g/mol.
Number of moles of aluminum = mass of aluminum / molar mass of aluminum
Number of moles of aluminum = 15 g / 26.98 g/mol
Step 2: Determine the number of moles of zinc chloride required based on the stoichiometry of the balanced equation.
From the balanced equation, we can see that 2 moles of aluminum react with 3 moles of zinc chloride.
So, the number of moles of zinc chloride = (Number of moles of aluminum * 3) / 2
Step 3: Calculate the mass of zinc chloride required using its molar mass.
The molar mass of zinc chloride (ZnCl2) is 136.29 g/mol.
Mass of zinc chloride required = number of moles of zinc chloride * molar mass of zinc chloride
Putting it all together, we have:
Number of moles of aluminum = 15 g / 26.98 g/mol
Number of moles of zinc chloride = (Number of moles of aluminum * 3) / 2
Mass of zinc chloride required = number of moles of zinc chloride * molar mass of zinc chloride
Calculating the above values will give us the mass of zinc chloride required to react with 15 grams of aluminum metal.