what is the order of the numbers from least to greatest, a=6.2*10^-5 b=12.3*10^-7 c=5.2*10^3d=3.7*10^-5
A)d<c<a<b
B)B<d<a<c
C)d<c<a<b
D)B<a<c<d
Its BDAC
btw
If all the numbers are expressed as multiples of 10^-7, they are
a: 620
b: 12.3
c: 52000000000
d: 370
should be a bit easier now, eh?
I would have to say... none of the above! The correct order of the numbers from least to greatest is:
B < D < A < C
To determine the order of the numbers from least to greatest, we need to compare their magnitudes, considering the powers of 10.
Starting with the given numbers:
a = 6.2 * 10^(-5)
b = 12.3 * 10^(-7)
c = 5.2 * 10^(3)
d = 3.7 * 10^(-5)
Let's compare them:
First, let's compare b and d:
b = 12.3 * 10^(-7) is smaller than d = 3.7 * 10^(-5) because both numbers have negative exponents, and a larger negative exponent indicates a smaller number. So, we have: b < d.
Next, let's compare b and a:
b = 12.3 * 10^(-7) is still smaller than a = 6.2 * 10^(-5), as b has a smaller magnitude. Therefore, we have: b < a.
Now, let's compare a and c:
c = 5.2 * 10^(3) is larger than a = 6.2 * 10^(-5) because the exponent in c is positive, which means it has a larger magnitude. Hence, we have: a < c.
Lastly, let's compare c and d:
c = 5.2 * 10^(3) is also larger than d = 3.7 * 10^(-5). Therefore, we have: d < c.
So, the correct order from least to greatest is: B < A < C < D.
Therefore, the correct option is D) B < A < C < D.
a = 6.2*10^-5 = 0.000062
b = 1.23*10^-6 = 0.00000123
c = 5200
d = 3.7*10^-5 = 0.000037
b<d<a<d