WHAT WILL BE THE GREATEST 5 DIGIT NUMBER WITH 7 ON ITS TENS PLACE AND WHEN ROUNDED OFF TO NEAREST HUNDREDS GIVES 76500?
wouldn't that have to be 76479 ?
76479
To find the greatest 5-digit number with 7 on its tens place and when rounded off to the nearest hundreds gives 76,500, we can follow these steps:
Step 1: Understand the problem.
We need to find a 5-digit number with 7 in its tens place that, when rounded off to the nearest hundreds, becomes 76,500.
Step 2: Analyze the conditions.
For a 5-digit number, we know that the greatest possible digit in the ten-thousands place is 9, and the smallest possible digit in the thousands place is 0. Since we want to round off the number to the nearest hundreds, the digit in the hundreds place will remain the same.
Step 3: Determine the digit in the thousands place.
To find the digit in the thousands place, we look at the rounding-off condition. Since rounding up occurs when the digit in the thousands place is 5 or greater, and we want the rounded-off number to be 76,500, we know that the digit in the thousands place is less than 5.
Step 4: Determine the digit in the ten-thousands place.
The ten-thousands place can have any digit from 0 to 9 since we want the greatest possible number.
Step 5: Determine the other digits.
Since we only need to have 7 in the tens place, the digit in the units place can be any digit from 0 to 9. The digit in the ones place is irrelevant for our requirements.
Step 6: Combine the digits to form the greatest 5-digit number.
Based on the conditions mentioned above, the greatest 5-digit number with 7 in the tens place and rounded off to the nearest hundreds as 76,500 is 97,700.