What is an equation for the translation (x - 2)^2 + (y + 1)^2 = 16 by 4 units left and 6 units up?
1) (x + 2)^2 + (y - 5)^2 = 16
2) (x - 2)^2 + (y - 5)^2 = 16
3) (x + 5)^2 + (y - 2)^2 = 16
4) (x + 4)^2 + (y - 5)^2 = 16
They mean the answer is A. Just took the assignment.
Does anyone have the whole test?
Anybody have the answers to the whole test
Legend has it that Anonymous is still looking for the test answers to this day
Anyone have answers to whole test?
Nvm the questions are different for everyone
I got yall hold up
i mean u could just write out the entire question and put the answer in
To find the equation for the translation of the given equation, we need to move the center point of the circle 4 units to the left and 6 units up.
The original equation is (x - 2)^2 + (y + 1)^2 = 16. To move the center point 4 units to the left, we need to subtract 4 from the x-coordinate of the center. To move the center point 6 units up, we need to add 6 to the y-coordinate of the center.
Subtracting 4 from the x-coordinate of the center, we get (x - 2 - 4)^2 + (y + 1)^2 = 16, which simplifies to (x - 6)^2 + (y + 1)^2 = 16.
Adding 6 to the y-coordinate of the center, we get (x - 6)^2 + (y + 1 + 6)^2 = 16, which simplifies to (x - 6)^2 + (y + 7)^2 = 16.
Therefore, the equation for the translation (x - 2)^2 + (y + 1)^2 = 16 by 4 units left and 6 units up is (x - 6)^2 + (y + 7)^2 = 16.
So, the correct answer is 4) (x - 6)^2 + (y + 7)^2 = 16.
the centre of (x - 2)^2 + (y + 1)^2 = 16
is (2,-1)
Now move that centre 4 units to the left and 6 units up
New centre is .......
new equation is .......