The pressure P, of a gas varies inversely with its volume, V. Pressure is measured in units of Pa. Suppose that a particular amount of a gas is initially at a pressure of 84 Pa at a volume of 36 L. If the volume is expanded to 216 L, what will the new pressure be? I don't just want the answer! I want to know how to solve this problem if possible.
answer is 28 pa just took the test. and I have all the answers if anyone needs them for connections academy. ;)
To solve this problem, we can use the inverse variation formula:
P1 * V1 = P2 * V2
where P1 and V1 are the initial pressure and volume, and P2 and V2 are the new pressure and volume.
Given:
P1 = 84 Pa
V1 = 36 L
V2 = 216 L
Let's plug in the given values into the formula:
84 * 36 = P2 * 216
Now, we can solve for P2:
3024 = P2 * 216
Divide both sides of the equation by 216:
3024 / 216 = P2
P2 ≈ 14
Therefore, the new pressure will be approximately 14 Pa.
To solve this problem, we can use the inverse variation formula:
P1 * V1 = P2 * V2
where P1 and V1 are the initial pressure and volume, and P2 and V2 are the new pressure and volume.
Given that the initial pressure, P1, is 84 Pa and the initial volume, V1, is 36 L, we can substitute these values into the formula:
84 Pa * 36 L = P2 * 216 L
To find the new pressure, P2, we need to isolate it on one side of the equation. Let's rearrange the formula:
P2 = (84 Pa * 36 L) / 216 L
Now, we can simplify the expression:
P2 = 3,024 Pa / 216 L
P2 = 14 Pa
Therefore, the new pressure, P2, is 14 Pa when the volume is expanded to 216 L.
P1*V1 = P2*V2
P2 =( 36*84)/216
P2= 14 Pa