A detailed picture illustrating an agricultural field in a rectangular shape, featuring dimensions of 100 meters by 42 meters. In one corner of the field, a well is being dug, its depth reaching 20 meters, while its diameter measures 14 meters. The earth that's being excavated from the well creation is being uniformly spread over the remaining area of the field. This scene should give the impression of a gradual increase in the level of the field.

an agriculture field is rectangular, with dimensions 100m by 42m.a 20 m deep well of diameter 14 m is dug in a corner of the field and the earth taken out is spread evenly over the remaining part of the field.find the increase in the level of the field

Volume Of well=22/7×7×7×20

=3,080m^3
Area Of filed =100×42= 4200m^2
The area of the remaning part of the filed=the area of field - the area of well, so. 4200m^2 - 154m^2 (22/7×7×7)=4046m^2
The volume of the riseing filed = the volume of the earth dug out
4046(h)=3080m^3
h=0.7612'm
=76cm።።።።just like hizki..

76

volume of well = π r^2 h

= π(7^2)(20)
= 98π m^3

surface area to be covered by dirt
= 100(42) - π(7^2)
=4200 - 49π m^2

let the depth of the dirt be h m

(4200 - 49π)h = 98π

check and do my arithmetic

Sorry , the answer is mighty 76.please help me! I am in confusion.!!!!!

You are really correct. My response is just like u.

(toliyad) the answer is 76cm dude

0.076

yes

calculate the volume and surface area of a right circular cylinder of height 1m and 70cm

The level of the field increased by 76 cm.