a stone is thrown vertically upward from tower takes 5 sec to reach ground the height of tower is

To find the height of the tower, we need to make some assumptions:

1. We assume there is no air resistance.
2. We assume the acceleration due to gravity is constant at 9.8 m/s^2.

Given that the stone takes 5 seconds to reach the ground, we can use the equations of motion to find the height (h) of the tower.

The equation for the height of an object moving vertically can be calculated using:

h = ut + (1/2)gt^2

Here:
- u is the initial velocity of the stone (when it was thrown upward).
- g is the acceleration due to gravity.
- t is the time it takes for the stone to reach the ground.

Since the stone is thrown upward, its initial velocity (u) will be positive. The final velocity (v) when the stone reaches the ground will be zero.

Using the equation of motion, we can rewrite it as:

v = u + gt

Since the final velocity (v) is zero at the peak of the stone's trajectory, we can write:

0 = u - gt

Rearranging this equation, we get:

u = gt

Substituting back into the equation for height:

h = (1/2)gt^2

Now, we can substitute the given values into the equation:

h = (1/2)(9.8)(5)^2
h = 122.5 meters

Therefore, the height of the tower is approximately 122.5 meters.