Chemistry

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The data below was collected while performing a titration of acetic acid (in vinegar) to determine its concentration using sodium hydroxide. 150 ml of vinegar with unknown molarity 45.5 ml of .5 M NaOH was added to reach equivalence point Find the molarity of the vinegar.

  • Chemistry -

    Let's call acetic acid HAc.
    HAc | NaOH ==> NaAc + H2O

    mols NaOH = M x L = ?
    mols HAc = mols NaOH
    M HAc = mols HAc/L HAc = ?

  • Chemistry -

    For a 1:1 rxn ratio of monoprotic acid reacting with a GpIA strong base use ...
    (Molarity x Volume)acid = (Molarity x Volume)base

    Molarity Acid
    = [(M x V)base]/(Vol Acid)
    = [(0.5M)(45.5 ml)]/(150 ml)
    = 0.16M HOAc

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