Write each series as a summation in sigma notation.

5+8+11+14

i=1

note that the numbers grow by 3's. So, the sequence is 3k+ something.

3*1=3, but the first term is 5, so the terms are

3k+2

The sum is thus

4
∑ 3k+2
k=1

To write the given series in sigma notation, we need to determine the general term for each term in the series.

The given series is 5, 8, 11, 14. We can observe that each term is obtained by adding 3 to the previous term. Therefore, the general term for this series can be defined as:

a_i = 5 + (i-1) * 3

Now, we can write the series as a summation in sigma notation:

Σ (5 + (i-1) * 3) , where i starts from 1 and goes upto the desired number of terms in the series.