The human egg cell above is magnified using a 10´ ocular lens and a 40´ high power objective lens.
(a) Calculate the overall magnification.
(b) If the field of view at high-power magnification is 400 mm, calculate the size of the field of view when the magnification is reduced to 200´. Round your answer to three significant digits.
(c) Convert your three-digit answer in (b) to millimetres.
i need help with this too
did you guys figure out the answer?
To calculate the overall magnification, you need to multiply the magnification of the ocular lens by the magnification of the objective lens.
(a) Overall Magnification:
Magnification of the ocular lens = 10´ (denoted as 10 times)
Magnification of the high-power objective lens = 40´ (denoted as 40 times)
Overall magnification = Magnification of the ocular lens * Magnification of the objective lens
Overall magnification = 10´ * 40´ = 400´
Therefore, the overall magnification is 400 times (400´).
(b) To calculate the size of the field of view when the magnification is reduced to 200´, we need to determine the new magnification ratio.
Magnification at high-power = 400´ (denoted as 400 times)
Magnification when reduced = 200´ (denoted as 200 times)
The magnification ratio (R1/R2) can be used to calculate the change in the field of view. The formula is:
Field of view at high-power / Field of view when reduced = R2^2 / R1^2
Substituting the values:
400 / Field of view when reduced = (200/400)^2
Simplifying:
Field of view when reduced = 400 * (200/400)^2
Calculating:
Field of view when reduced = 400 * 0.5^2
Field of view when reduced ≈ 400 * 0.25
Field of view when reduced ≈ 100 mm
Therefore, the size of the field of view when the magnification is reduced to 200´ is approximately 100 mm.
(c) To convert the answer in (b) to millimetres, we already have the field of view in millimetres.
The size of the field of view when the magnification is reduced to 200´ is approximately 100 mm.
Therefore, the answer in (b) is already in millimetres.