rajeev,
who is sixteen years old, is four times as old as his sister. How old will Rony be when he is twice as old as his sister?
16 = 4S
S = 4
16+x = 2(4+x)
Solve for x.
24
To answer the question, we first need to determine the age of Rajeev's sister. We are given that Rajeev is currently sixteen years old and four times as old as his sister. Thus, we can set up an equation:
Rajeev's age = 4 * sister's age
Since Rajeev is currently sixteen, we can substitute this value into the equation:
16 = 4 * sister's age
Next, we solve the equation for the sister's age:
sister's age = 16 / 4 = 4 years
Now that we know the sister's age, we can determine the age at which Rony will be twice as old as his sister. Since Rajeev is currently sixteen years old, Rony's age can be represented as:
Rony's age = sister's age + x
Where x represents the number of years in the future. We need to find the value of x that makes Rony twice as old as his sister. Mathematically, this can be represented as:
2 * sister's age = Rony's age
Substituting sister's age as 4, we get:
2 * 4 = Rony's age
Rony's age = 8
Therefore, Rony will be 8 years old when he is twice as old as his sister.