A jar of gumballs contains 50 red gumballs, 45 yellow gumballs, and 30 green gumballs. You randomly select a gumball, then select another without putting it back. What is the probability that you draw two red gumballs as a percent and a fraction in simplest form?
50/125*49/124= answer
subtract 1 from the denominator becuz u took one gumball and didn't replace it.
To find the probability of drawing two red gumballs, we can calculate the probability of drawing the first red gumball and then the probability of drawing the second red gumball without replacement.
Step 1: Calculate the probability of drawing the first red gumball.
There are a total of 50 + 45 + 30 = 125 gumballs in the jar. Out of these, 50 are red gumballs. So, the probability of drawing a red gumball on the first draw is 50/125.
Step 2: Calculate the probability of drawing the second red gumball without replacement.
After taking out one red gumball, there are now 49 red gumballs left in the jar. The total number of gumballs remaining is 125 - 1 = 124. So, the probability of drawing a second red gumball without replacement is 49/124.
Step 3: Calculate the overall probability.
We multiply the probabilities from step 1 and step 2 to get the overall probability of drawing two red gumballs: (50/125) * (49/124) = 0.196 (rounded to three decimal places).
To express this probability as a fraction in simplest form, we can write it as 49/250.
Finally, to express the probability as a percent, we multiply the probability by 100: 0.196 * 100 = 19.6%.
Therefore, the probability of drawing two red gumballs is 19.6% or 49/250.