A plane flies from new york to chicago (a distance of 1,600 miles) at 400 mph. Returning from Chicago to New York it flies into a headwind and averages only 320 mph. How many hours total was the plane in the air for the entire trip?
since distance/speed = time,
(1600/400) + (1600/320) = ?
To find the total time the plane was in the air for the entire trip, we need to calculate the individual times for each leg of the journey and add them together.
Let's begin with the first leg of the trip from New York to Chicago.
Distance: 1,600 miles
Speed: 400 mph
To find the time, we divide the distance by the speed:
Time = Distance / Speed
Time = 1,600 miles / 400 mph
Time = 4 hours
So, the plane took 4 hours to fly from New York to Chicago.
Now let's move on to the return journey from Chicago to New York.
Distance: 1,600 miles
Speed: 320 mph
Using the same formula as before:
Time = Distance / Speed
Time = 1,600 miles / 320 mph
Time = 5 hours
Therefore, the plane took 5 hours to fly from Chicago to New York.
Finally, to find the total time, we add the time for both legs:
Total time = 4 hours + 5 hours
Total time = 9 hours
So, the plane was in the air for a total of 9 hours for the entire trip.
To calculate the total time the plane was in the air for the entire trip, we need to consider the time it took for both the outbound and inbound journeys.
First, let's calculate the time for the outbound journey:
Distance from New York to Chicago = 1,600 miles
Speed during the outbound journey = 400 mph
To find the time, we use the formula: time = distance / speed
Time for outbound journey = 1,600 miles / 400 mph = 4 hours
Next, let's calculate the time for the return journey:
Speed during the return journey = 320 mph
Time for return journey = 1,600 miles / 320 mph = 5 hours
Now, let's find the total time:
Total time = Time for outbound journey + Time for return journey
Total time = 4 hours + 5 hours = 9 hours
Therefore, the plane was in the air for a total of 9 hours for the entire trip.