A boat takes 1 hour less to go 200 miles downstream than upstream. If the rate of the current is 3 miles per hour, what is the rate of the boat in still water?

since distance/speed = time,

200/(x+3) = 200/(x-3) - 1

Let's assume the rate of the boat in still water is 'B' miles per hour.

When the boat is going downstream, the rate of the boat in still water is increased by the rate of the current. So, the effective rate is 'B + 3'.
When the boat is going upstream, the rate of the boat in still water is decreased by the rate of the current. So, the effective rate is 'B - 3'.

Given that the boat takes 1 hour less to go 200 miles downstream than upstream, we can set up the following equation:

200 / (B + 3) = 200 / (B - 3) + 1

Cross multiplying, we get:

200(B - 3) = 200(B + 3) + (B + 3)(B - 3)

Expanding the equation, we get:

200B - 600 = 200B + 600 + B^2 - 9

Simplifying, we get:

B^2 - 9 = 1200

Rearranging the equation, we get:

B^2 = 1209

Taking the square root of both sides, we get:

B = √1209

Therefore, the rate of the boat in still water is approximately 34.78 miles per hour.

To find the rate of the boat in still water, we can use the formula:

Rate of boat in still water = (Rate downstream + Rate upstream) / 2

Let's break down the problem:
Let's assume the rate of the boat in still water is "B" miles per hour (mph).
Given that the rate of the current is 3 mph, we can calculate the rate downstream and rate upstream as follows:

Rate downstream = B + 3 mph
Rate upstream = B - 3 mph

Now, we are given that the boat takes 1 hour less to go 200 miles downstream than upstream. We can set up the following equation to represent this:

200 / (B + 3) = 200 / (B - 3) + 1

To solve this equation, we can cross-multiply:

200(B - 3) = 200(B + 3) + 1(B + 3)

Now, simplify the equation:

200B - 600 = 200B + 600 + B + 3

Combine like terms:
200B - 200B - B = 600 + 603

Simplify further:
-B = 1203

Divide by -1 on both sides to isolate B:
B = -1203

Since a negative rate does not make sense in this context, it is likely that there was an error in solving the equation or setting it up. Please double-check the calculations and equations and try again.