posted by Chuck
A 15.0 g sample consisting of a mixture of silver nitrate and sodium nitrate is dissolved
in water. This aqueous mixture then reacts with aqueous potassium chloride to form
3.97 g of solid. Calculate the percent by mass of silver nitrate in the first mixture.
AgNO3 + KCl ==> AgCl + KNO3.
NaNO3 + KCl ==> no reaction.
So you obtained 3.97 g AgCl. Convert that to g AgNO3 this way.
3.97 x (molar mass AgNO3/molar mass AgCl) = ? g AgNO3.
%AgNO3 = (g AgNO3/mass sample)*100 = ?