A person walks 25 northeast 3.10km.How far would she have to walk due north and due east to arrive at the same point?

3.10km[25o]. 3.1*sin25 = 1.31 km

due north, 3.1*Cos25 = 2.81 km due east.

I assumed you meant 25o N. of E, because northeast = 45o.

To solve this problem, we can use basic trigonometry.

First, let's visualize the person's movement. The person starts at a particular point and walks 3.10 km in a northeast direction.

We know that walking northeast is a combination of walking north and east. So, we need to find out how much of the 3.10 km is in the north direction and how much is in the east direction.

Using trigonometry, we can break down the northeast direction into its north and east components.

The northeast direction is a combination of north and east, and since northeast is a 45° angle, we can assume it forms a right-angled triangle.

To find the north and east components, we can use the sine and cosine of the 45° angle.

sin(45°) = opp/hyp = north/3.10 km
cos(45°) = adj/hyp = east/3.10 km

Since sin(45°) = cos(45°), we can conclude that north = east.

So, the person would have to walk 1.55 km due north and 1.55 km due east to arrive at the same point.