The following relationship is known to be true for two angles A and B:

cos(A)cos(B)-sin(A)sin(B)=0.957269

Express A in terms of the angle B. Work in degrees and report numeric values accurate to 2 decimal places.

So I'm pretty lost on how to even begin this problem. I do know the product-to-sum identities such as cos(a)cos(b)=1/2(cos(a+b)+cos(a-b))
Any help is greatly appreciated!

all you need is the sum formula for cosines.

in other words,
cos(A+B) = .957269
A+B = 16.81°

Correction:

Sum and difference identities is what I meant to say:

cos(a+b)=cos(a)cos(b)-sin(a)sin(b)

I tried putting in inverse cos(.957269) and the math site didn't like my answer. It tells me to enter it as an expression. Any ideas what I'm doing wrong?

try arccos(.957269)

It's still not working, weird.

To solve the given equation and express angle A in terms of angle B, we can use the product-to-sum identities you mentioned. Let's start with the given equation:

cos(A)cos(B) - sin(A)sin(B) = 0.957269

Using the product-to-sum identity for cosine, we can rewrite the left-hand side of the equation:

[(1/2)(cos(A + B) + cos(A - B))] - sin(A)sin(B) = 0.957269

Next, let's substitute the product-to-sum identity for sine:

[(1/2)(cos(A + B) + cos(A - B))] - [(1/2)(cos(A - B) - cos(A + B))] = 0.957269

Now, simplify the equation:

(1/2)(cos(A + B) + cos(A - B) - cos(A - B) + cos(A + B)) = 0.957269

The cos(A - B) and -cos(A - B) terms cancel out, leaving:

(1/2)(2cos(A + B)) = 0.957269

Simplifying further:

cos(A + B) = 1.914538

Now, to express A in terms of B, we need to use the inverse cosine function (arccos or cos^(-1)). Taking the inverse cosine of both sides:

A + B = arccos(1.914538)

Since we want to express A in terms of B, we need to isolate A:

A = arccos(1.914538) - B

Now we can plug in the value of B to find the specific value for angle A. Remember to work in degrees and round the final answer to two decimal places.

Note: It's important to mention that the equation provided (cos(A)cos(B)-sin(A)sin(B)=0.957269) does not have unique solutions. The angle values depend on the chosen value for B.