you spin a 6 section red spinner and a 6 section blue spinner. Find P(red less than 4 and a red 2).
Okay well the probability for the first it would be
P= 6/12 or 1/2 simplified. or 50%
second is
P= 1/12 .percent is 8%
thank you.
anytime :)
To find the probability of both spinning a red less than 4 and a red 2, we need to determine the probability of each event separately and then multiply them together.
Let's start with the first event, which is spinning a red less than 4. The red spinner has 6 sections, so we need to count the number of red sections that are less than 4. From the information provided, it is not clear whether the red spinner is numbered from 1 to 6 or 0 to 5. For the sake of this explanation, let's assume it is numbered from 1 to 6.
So, the red sections that are less than 4 would be 1, 2, and 3. Therefore, there are 3 favorable outcomes for the first event.
Now let's move on to the second event, spinning a red 2. Since we have already determined that the red spinner has a section numbered 2, there is only 1 favorable outcome for the second event.
To find the probability, we need to divide the number of favorable outcomes by the total number of possible outcomes. In this case, the red spinner has 6 sections, so there are 6 possible outcomes for both events.
So, the probability of spinning a red less than 4 and a red 2 is (3/6) * (1/6), which simplifies to 1/12.
Therefore, the probability of spinning a red less than 4 and a red 2 is 1/12.