the room is rectangular and measures 9 feet on one side and 15 feet on the other. she needs 0.5 ounces of paint per spuare foot. how much paint does she need?
How high is the wall?
L=15,B=9(Rectangle), sqrs in rectangle=let x be number of sqrs in rectangle,and L be length of sides:15*9=x*(L*L)
divide both sides by x= 15*9/x=L*L,square root both sides,then cross-multiply rootx and equate 3*root15=L*rootx
x=15,L=3,in each sqrs we have 9foot sqrs,0.5 ounce per foot sqr=0.5*9=4.5,there are 15 sqrs, ounce of paint=4.5*15=67.5
67.5
To calculate the amount of paint needed, you will need to determine the area of the room and then multiply it by the paint requirement per square foot.
First, find the area of the room:
Area = Length × Width
Given that the length is 9 feet and the width is 15 feet:
Area = 9 feet × 15 feet
Area = 135 square feet
Now, multiply the area by the paint requirement per square foot (0.5 ounces/sq ft):
Amount of paint needed = Area × Paint requirement per square foot
Amount of paint needed = 135 square feet × 0.5 ounces/square foot
Amount of paint needed = 67.5 ounces
Therefore, she will need 67.5 ounces of paint to cover the room.