Iron and oxygen gas can react to form the magnetic oxide of iron Fe3O4. How many grams of Fe3O4 can be made from 42.3 g of Fe?
3Fe + 2O2 ==> Fe3O4
mols Fe = grams/atomic mass Fe = ?
Using the coefficients in the balanced equation, convert mols Fe to mols Fe3O4.
Now convert mols Fe3O4 to grams. g = mols x molar mass = ?
To calculate the grams of Fe3O4 that can be made from 42.3 g of Fe, we need to determine the stoichiometry of the reaction. The balanced chemical equation for the reaction between iron (Fe) and oxygen (O2) to form Fe3O4 is:
4Fe + 3O2 -> 2Fe3O4
From the balanced equation, we can see that 4 moles of Fe react with 3 moles of O2 to produce 2 moles of Fe3O4. Moles are a useful unit when dealing with chemical reactions and stoichiometry.
To find the moles of Fe in the given quantity of 42.3 g, we need to use the molar mass of Fe, which is 55.85 g/mol. We can calculate the moles of Fe using the formula:
moles of Fe = mass of Fe / molar mass of Fe
moles of Fe = 42.3 g / 55.85 g/mol
moles of Fe = 0.757 mol (approximately)
Based on the stoichiometry of the reaction, we know that 4 moles of Fe will react to produce 2 moles of Fe3O4. To find the moles of Fe3O4 that can be produced, we can set up a simple ratio:
4 mol Fe : 2 mol Fe3O4
Since we have 0.757 mol of Fe, we can calculate the moles of Fe3O4 using the ratio:
moles of Fe3O4 = (2 mol Fe3O4 / 4 mol Fe) * 0.757 mol Fe
moles of Fe3O4 = 0.3785 mol (approximately)
Finally, to find the mass of Fe3O4, we need to use the molar mass of Fe3O4, which is 231.53 g/mol. We can calculate the mass using the formula:
mass of Fe3O4 = moles of Fe3O4 * molar mass of Fe3O4
mass of Fe3O4 = 0.3785 mol * 231.53 g/mol
mass of Fe3O4 = 87.6 g (approximately)
Therefore, approximately 87.6 grams of Fe3O4 can be made from 42.3 g of Fe.