# Algebra

posted by Anonymous

1=√(-2v-3)

√(n+5)= √(5n-11)

12. Tell which solutions, if any, are extraneous for each question.

√(12-n)=n;
n= -4,n=3

1. Steve

#10. since 1=√1, you must have -2v-3 = 1

#11.
√(n+5)= √(5n-11)
n+5 = 5n-11
n = 4
check: √9 = √9

#12. well, geez, just check them!
√(12-(-4)) = √(12+4) = √16 = 4 Since this is not equal to -4, that value is extraneous.
√(12-3) = √9 = 3
yep, that one is ok.

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