What is the empirical formula of benzene, C6H6?

I know how to find empirical formula; as long as you know the moles, you can find the ratio and thus the empirical formula. But the question provides nothing and I can only find the Mr?
The answer from the answer booklet is CH.

How is this answer obtained?

To find the empirical formula of benzene (C6H6), you need to determine the simplest whole-number ratio of the atoms in the compound.

The molecular formula C6H6 indicates that there are six carbon atoms and six hydrogen atoms in the compound. To find the empirical formula, you need to find the ratio of these atoms.

First, determine the molar mass of benzene (C6H6). Carbon has a molar mass of 12.01 g/mol, and hydrogen has a molar mass of 1.008 g/mol. Multiply the molar mass of carbon by the number of carbon atoms and the molar mass of hydrogen by the number of hydrogen atoms in the molecular formula:

(12.01 g/mol) x 6 = 72.06 g/mol (total molar mass of carbon in benzene)
(1.008 g/mol) x 6 = 6.048 g/mol (total molar mass of hydrogen in benzene)

To find the empirical formula, divide the molar mass of each element by the molar mass of the compound:

Empirical formula of carbon = (72.06 g/mol) / 72.06 g/mol = 1
Empirical formula of hydrogen = (6.048 g/mol) / 72.06 g/mol ≈ 0.0839

Next, you need to convert the ratio of each element to the smallest whole-number ratio. Multiplying the ratio by a factor that will give whole numbers will achieve this. In this case, we will multiply by 12 to get rid of the decimal:

Carbon: 1 x 12 = 12
Hydrogen: 0.0839 x 12 = 1

After multiplying by 12, the ratio becomes 12:1. This means that the empirical formula of benzene is CH.

So, to summarize, the empirical formula of benzene (C6H6) is CH.

To determine the empirical formula of benzene (C6H6), you need to find the simplest whole number ratio of the atoms present in the molecule.

Start by calculating the molar mass of the molecule benzene:
- Carbon (C) has a molar mass of 12.01 g/mol.
- Hydrogen (H) has a molar mass of 1.01 g/mol.

Multiply the number of carbon atoms by the molar mass of carbon:
6 carbon atoms * 12.01 g/mol = 72.06 g/mol.

Multiply the number of hydrogen atoms by the molar mass of hydrogen:
6 hydrogen atoms * 1.01 g/mol = 6.06 g/mol.

Add up the total molar mass of carbon and hydrogen:
72.06 g/mol + 6.06 g/mol = 78.12 g/mol.

Now, find the ratio of moles of carbon to moles of hydrogen by dividing the moles of each by their respective molar masses:
Moles of carbon = 72.06 g / 12.01 g/mol ≈ 6 moles.
Moles of hydrogen = 6.06 g / 1.01 g/mol ≈ 6 moles.

Divide both moles by the smallest number of moles (in this case, 6):
6 moles / 6 = 1 mole (carbon)
6 moles / 6 = 1 mole (hydrogen)

This simplified ratio indicates that the empirical formula of benzene is CH, as there is a 1:1 ratio of carbon to hydrogen.

empirical: CH

Empirical is the lowest whole ratio of atoms.