The length of a rectangle is three times the width of the rectangle. If the width of the rectangle is y units, what is the area of the rectangle?
width --- y
length --- 3y
area = y(3y) or 3y^2
To find the area of a rectangle, we multiply its length by its width.
Given that the length of the rectangle is three times the width, we can express the length as 3y units.
So, the area of the rectangle is:
Area = Length x Width
= (3y) x y
= 3y^2
Therefore, the area of the rectangle is 3y^2 square units.
To find the area of the rectangle, we need to multiply its length by its width. Let's call the length of the rectangle L and the width of the rectangle W. According to the problem, the length L is three times the width W.
We can represent this information as an equation: L = 3W.
Given that the width of the rectangle is y units, we can substitute y for W in the equation above: L = 3y.
To find the area of the rectangle, we multiply the length and width: Area = L × W.
Substituting the values for L and W, we get: Area = (3y) × y.
Simplifying the expression, we get: Area = 3y^2.
Therefore, the area of the rectangle is 3y^2 square units.