Questions LLC
Login
or
Sign Up
Ask a New Question
Science
Physics
a stone of mass 50g is released from rest, Calculate it's kinetic energy after 6s from the beginning of the motion
1 answer
V = Vo + g*t = 0 + 9.8*6 = 58.8 m/s.
KE = 0.5M*V^2, M = 0.05 kg.
You can
ask a new question
or
answer this question
.
Similar Questions
A bullet of mass 50g is fired with a velocity of 200m/s in to a block of mass 950g at rest. Given the block can more firely,
Top answer:
Conservation of Momentum mv=(M+m)V' solve for V' KE after impact = 1/2 (m+M)V'^2 energy lost:1/2
Read more.
A stone of mass 0.55 kilograms is released and falls to the ground. Measurements show that the stone has a kinetic energy of 9.8
Top answer:
Ke = (1/2) m v^2 = (1/2) (.55) v^2 = 9.8 v^2 = 35.6 v = 5.97 m/s to get height m g h = 0.55 * 9.81 *
Read more.
A stone of mass 0.55 kilograms is released and falls to the ground. Measurements show that the stone has a kinetic energy of 9.8
Top answer:
7.2
Read more.
The potential energy of a catapult was completely converted into kinetic energy by releasing a small stone with a mass of 20
Top answer:
Calculate the distance between two points A(3,4) and B(2,1)
Read more.
A stone of mass 0.5kg is thrown to a height 200m.
(A). What is its kinetic energy and potential energy in its maximum height.
Top answer:
To answer these questions, we need to understand the concepts of kinetic energy, potential energy,
Read more.
An explosion breaks an object initially at rest into two pieces, one of which has 2.0 times the mass of the other. If 7300 J of
Top answer:
To find the kinetic energy acquired by the lighter piece, we can use the principle of conservation
Read more.
A 278 g particle is released from rest at point A inside an smooth hemispherical bowl of radius 36.5 cm, as shown below.
(a)
Top answer:
To answer these questions, we need to apply the principles of conservation of energy. The total
Read more.
A 245 g particle is released from rest at point A inside a smooth hemispherical bowl of radius 35.0 cm, as shown in Figure 5-21.
Top answer:
To answer these questions, let's break down the problem step by step: (a) To calculate the
Read more.
A 2.48-kg rock is released from rest at a height of 28.1 m. Ignore air resistance and determine (a) the kinetic energy at 28.1
Top answer:
PE = m x g x h PE = 2.48 x 9.8 x 28.1 PE = 682.94J at 28.1m KE at 28.1m = 0, because the object is
Read more.
A 2.48-kg rock is released from rest at a height of 28.1 m. Ignore air resistance and determine (a) the kinetic energy at 28.1
Top answer:
dafs
Read more.
Related Questions
A curling stone with a mass of 18 kg slides 38m across a sheet of ice in 8.0 s before it stops because of friction. What is the
A stone of mass 50g is accelerated from a catapult to a speed of 8.0 ms-1 from rest over a distance of 30 cm. What average force
A 20.0kg curling stone at the hog line and moves 28.35m [west] to sit on the button and score a point. If the coefficient of
A stone of mass 5g is projected with a rubber catapult. If catapult stretch though a distance of 7cm by an average force of 70n,
A ball with mass of 2kg rolls from rest , down an incline of 10° neglecting friction. Calculate the kinetic energy after it has
A 5.36 kg object falls freely (ignore air resistance), after being dropped from rest. Determine the initial kinetic energy, the
A curling stone with mass 19.00 kg is released with an initial speed v0 sliding on level ice. The coefficient of kinetic
A 2.5 kg stone is released from rest and falls toward earth. After 4s, the magnitude of its momentum is:
My work: J=F*t =(F *t)=
A stone that starts at rest is in free fall for 8.0 s.
a.Calculate the stone's velocity after 8.0 s. b. What is the stone's
We can calculate the kinetic energy of any moving object with a very simple formula: kinetic energy = 1/2 mv^2 ,where m is the
