What volume of coffee (pH=5.0) would be required to have .25 moles of H3O+ ions? (must be two steps)
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(1) [H3O^+] = 10^-pH = 10^-5 mol/Liter
(2) 0.25moles(H3O^+)/(10^-5)mol H3O^+/Liter = 25,000 Liters
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To determine the volume of coffee required to have 0.25 moles of H3O+ ions, we need to follow a two-step process:
Step 1: Calculate the concentration of H3O+ ions in the coffee solution.
Step 2: Use the concentration to find the volume of coffee.
Step 1: Calculate the concentration of H3O+ ions in the coffee solution.
The concentration of H3O+ ions can be determined using the equation:
pH = -log[H3O+]
We are given that the pH of coffee is 5.0, so we substitute the value into the equation:
5.0 = -log[H3O+]
Rearrange the equation to isolate [H3O+]:
[H3O+] = 10^(-pH)
Calculate the concentration of H3O+:
[H3O+] = 10^(-5.0)
Step 2: Use the concentration to find the volume of coffee.
The formula to calculate the moles of a substance is:
moles = concentration × volume
Rearrange the equation to solve for volume:
volume = moles / concentration
In this case, we want to find the volume when we have 0.25 moles of H3O+ ions, so:
volume = 0.25 moles / [H3O+]
Substitute the concentration value we calculated in Step 1 and solve for volume:
volume = 0.25 moles / (10^(-5.0))
Calculate the volume using a scientific calculator or by performing the calculations step by step.
Please note that the units of volume will depend on the units used for the moles. If the moles are given in liters (L), the volume will be in liters as well. If the moles are given in milliliters (mL), the volume will be in milliliters.