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Neptunium 239
93 Np has a decay constant of 3.40 ×10-6 s-1. A 3.0-mg sample of Np-239 is prepared. The activity of the Np-239
Top answer:
activity=dN/dt=3.4E-6*3grams/239 *avagradros number.
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Neptunium 239
93 Np has a decay constant of 3.40 ×10-6 s-1. A 3.0-mg sample of Np-239 is prepared. The activity of the Np-239
Top answer:
Ok, take the last I gave you, and divide by 3.7E10
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Suppose you had a detection device that could count every decay event from a radioactive sample of plutonium-239.052156 (t1/2 is
Top answer:
To calculate the number of counts per second obtained from a sample of plutonium-239, you need to
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Pu-239 has a half-life of 24110 y. If 1.00 kg of this isotope is present in the used fuel rods of a nuclear power plant
Top answer:
k = 0.693/t<sub>1/2</sub> Calculate k and substitute into the equation below. ln(No/N) = kt For No
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If the half life of Pu-239 is 2.4 x 10^4 years, how many years are required for a 20-gram sample of plutonium-239 to be reduced
Top answer:
5 / 20 = 1/4 = (1/2)^2 2 half-lives
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_The_Natural_Base_e_
An accident in 1986 at the Chernobyl nuculear plant in the Ukraine released a large amount of plutonium
Top answer:
17g A=(.5)t/k
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Plutonium-239 is used in nuclear bombs. Determine the number of protons and neutrons in plutonium-239.
I really don't understand
Top answer:
To determine the number of protons and neutrons in plutonium-239, you will need to consult the
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what is theta, the x component, and the y component if you know the following
standard vector notation: 239 m @ 261 degrees
Top answer:
theta is 261, a rather odd question. y=239cos261=-35.4 x=239sin261=-236 This is a very odd question,
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Use 3.14 as pi. Use the formula V= pi x radius squared x height. Round to nearest tenth of a unit. Hint: 239/3.14/6 =
Top answer:
V= pi x r^2 x h 239 = 3.14 x r^2 x 6 239/3.14/6 = r^2 12.68577495 = r^2 r = √(12.68577495) r ≈
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Question: "Plutonium isotope Pu-239 has a half-life of 24,100 years. Suppose that 10 grams of Pu-239 was released in the
Top answer:
y = a e^(kt) where a is the initial amount so y = 10(e^(kt)) when t = 24100, y = 5 ---> you should
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Related Questions
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does anyone know if 239 over 58 is rational or irrational. Also the square root of 17.
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Identify the corresponding word problem, given the inequality: 16x ≥ 384
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Question Use the correct formula to find the area of a circle if the diameter is 21 mi. Round to the nearest
Neptunium-239 has a half-life of 2.35 days. How many days must elapse for a sample of 239-Np to decay to 1.00% of its original
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